A 2meters crowbar is employed to lift a load 300kg. What force must be applied to one end of the crowbar when a stump acting as a fulcrum is placed under the crowbar 0.5meter away from the end on which the load rests? Neglect the weight of the crowbar.

Answer 1

the lifting force is applied 3 times as far from the fulcrum as the load

f = m * g / 3 = (300 kg * 9.81 m/s^2) / 3

Answer 2

F1 = applied force.
F2 = M*g = 300*9.8 = 2940 N. = force of the load.

F1*d1 = F2*d2.
F1*1.5 = 2940*0.5,
F1 = ___ Newtons.