A 2kg hallow sphere of a radius 6cm starts from rest and rolls without slipping down a 10 degree incline. if the length of the incline is 50cm then the velocity of the center of mass of the hallow sphere at the bottom of the incline is?

Answer 1

if it rolling, then the angular velocity is related to velocity as
w=v/r

the energy gravity gives up is

mg(.50*sin10)

The energy in the sphere is
1/2 I w^2 + 1/2 m v^2=
1/2 I v^2/r^2+1/2 m v^2

look up I (moment of inertia) for a hollow sphere, set KE = initial PE, and solve for v. Your teacher is too easy.