In the division problem, the a in the numerator and the a in the denominator cancel each other.
a = 2/-5
a = -(2/5)
a=2a/(a-5)
How do I work this out?
2 answers
a=2a/(a-5)
*note: don't cancel the variable a (though it can be canceled since a can be factored from the left side and right side of equation),,
a^2 - 5a = 2a
a^2 - 7a = 0
a = 0 and a = 7
*notice that if you cancel a, equation becomes:
1=2/(a-5)
a - 5 = 2
a = 7
..in which you did not get the root a = 0
so there,, :)
*note: don't cancel the variable a (though it can be canceled since a can be factored from the left side and right side of equation),,
a^2 - 5a = 2a
a^2 - 7a = 0
a = 0 and a = 7
*notice that if you cancel a, equation becomes:
1=2/(a-5)
a - 5 = 2
a = 7
..in which you did not get the root a = 0
so there,, :)
2 answers