the neutralization equation:
concAcid*VolumeAcid=concBase*volumebase
29ml*Normality acid=.1M*24.63ml
Normality acid= 2.463/29= 0.085N
molarity acid*3=.085
molarity acid= .028 M
A 29.00 mL sample of an unknown H3PO4 solution is titrated with a 0.100 M NaOH solution. The equivalence point is reached when 24.63 mL of NaOH solution is added?
What is the concentration of the unknown H3PO4 solution? The neutralization reaction is
H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4(
How would I solve this equation?
Thanks!
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