A 2700 kg car traveling to the north is slowed down uniformly from an initial velocity of 29.8 m/s by a 7540 N braking force acting opposite the car’s motion.

Question

A 2700 kg car traveling to the north is slowed down uniformly from an initial velocity of 29.8 m/s by a 7540 N braking force acting opposite the car’s motion.
a) What is the car’s velocity after 2.77 s? Answer in units of m/s.

Henry · Answer

F = M*a = -7540 N. a = -7540/M = -7540/2700 = -2.79 m/s^2. V = Vo + a*t, V = 29.8 - 2.79*2.77 = 22.1 m/s.