Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A 27-kg boy stands 4 m from the center of a frictionless playground merry-go-round, which has a moment of inertia of 238 kg m2....Asked by Really stuck in this problem !!
A 27-kg boy stands 4 m from the center of a frictionless playground merry-go-round, which has a moment of inertia of 238 kg m2. The boy begins to run in a circular path with a speed of 0.6 m/s relative to the ground.
(a) Calculate the angular velocity of the merry-go-round.
(b) Calculate the speed of the boy relative to the surface of the merry-go-round.
(a) Calculate the angular velocity of the merry-go-round.
(b) Calculate the speed of the boy relative to the surface of the merry-go-round.
Answers
Answered by
drwls
(a) Total angular momentum remains zero as the merry-go-round and the boy move in opposite directions.
M*V*R - I*w = 0
Solve for w
w = MVR/I = 27*0.6*4/238 = 0.27 rad/s
(b) Relative velocity to platform below the boy = V - (-R*w) = V + R*w
M*V*R - I*w = 0
Solve for w
w = MVR/I = 27*0.6*4/238 = 0.27 rad/s
(b) Relative velocity to platform below the boy = V - (-R*w) = V + R*w
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.