A 26.7 g sample of ethylene glycol, a car radiator coolant, loses 668 J of heat. What was the initial temperature of ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/gK)?

Answer 1

Q=mc∆t
Q = heat energy
m = mass
c = specific heat (of ethylene glycol)
∆t= change in temperature (= final - initial temp)