Asked by Daisy
A 26.0 g object moving to the right at 17.0 cm/s overtakes and collides elastically with a 10.0 g object moving in the same direction at 15.0 cm/s. Find the velocity of each object after the collision.
a) 26.0 g object
b) 10.0 g object
a) 26.0 g object
b) 10.0 g object
Answers
Answered by
drwls
The center of mass of the two objects moves to the right at a velocity
(26*17 + 10*15)/(26 + 10) = 16.44 m/s
Consider what happens in a coordinate system travelling the the CM.
a) The heavier object comes from the right at velocity 17-16.44 = 0.56 cm/s and leaves at -0.56 cm/s.
b) The lighter object approaches from the left at velocity 15 - 16.44 = -1.44 cm/s and leaves with velocity +1.44 m/s.
Transfering back to lab coordinate sytem (by adding +16.44 to both velocities) , the final velocity of the heavier object is -0.56 + 16.44 = 15.88 cm/s, and the lighter object is +1.44 + 16.44 =
17.88 cm/s.
The above is a shortcut compared to solving both the momentum and energy cnservation equations for two unknowns. It should give the same reult if I did the math right.
(26*17 + 10*15)/(26 + 10) = 16.44 m/s
Consider what happens in a coordinate system travelling the the CM.
a) The heavier object comes from the right at velocity 17-16.44 = 0.56 cm/s and leaves at -0.56 cm/s.
b) The lighter object approaches from the left at velocity 15 - 16.44 = -1.44 cm/s and leaves with velocity +1.44 m/s.
Transfering back to lab coordinate sytem (by adding +16.44 to both velocities) , the final velocity of the heavier object is -0.56 + 16.44 = 15.88 cm/s, and the lighter object is +1.44 + 16.44 =
17.88 cm/s.
The above is a shortcut compared to solving both the momentum and energy cnservation equations for two unknowns. It should give the same reult if I did the math right.
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