A 25kg chair initially at rest on a horizontal floor requires a 165N horizontal force to set it in motion once the chair is in a 127n horizontal force keeps it moving a a constant velocity

Find the coefficient of static friction between the chair and floor

1 answer

To find the coefficient of static friction between the chair and the floor, we need to use the equation:

static friction = coefficient of static friction * normal force

where the normal force is equal to the weight of the chair.

The weight of the chair can be calculated using the formula:

weight = mass * gravity

where the mass of the chair is 25 kg and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore:

weight = 25 kg * 9.8 m/s^2
weight = 245 N

Now, we can use the given information to calculate the force required to set the chair in motion, and the force required to keep it moving at a constant velocity.

The force required to set the chair in motion is 165 N, and the force required to keep it moving at a constant velocity is 127 N.

The force required to set the chair in motion is equal to the sum of the force of static friction and the applied force:

165 N = static friction + 127 N

To find the coefficient of static friction, we rearrange the equation to solve for the frictional force:

static friction = 165 N - 127 N
static friction = 38 N

Now we can substitute the known values into the equation for static friction:

38 N = coefficient of static friction * 245 N

Solving for the coefficient of static friction:

coefficient of static friction = 38 N / 245 N
coefficient of static friction ≈ 0.155

Therefore, the coefficient of static friction between the chair and the floor is approximately 0.155.