Centripetal (centrifugal ) acceleration a= 2 m/s²
a=v²/R
v=sqrt(aR) =sqrt(2•200) =20 m/s
Centripetal force is F=ma= 2500•2 = 5000 N
http://www.engineeringtoolbox.com/centripetal-acceleration-d_1285.html
a 2500kg car is rounding a circular turn of radius 200m at constant speed. the magnitude of its acceleration is 2m/s2.what is the speed of the car? how much is the centripetal force?how much is the centrifugal acceleration?
2 answers
For the speed of the car (V), solve
V^2/R = 2 m/s^2
V = sqrt400 = 20 m/s
The centripetal force is
(acceleration)*(Mass) = 2*2500 = 5000 N
Centrifugal acceleration is the opposite of centripetal acceleration
V^2/R = 2 m/s^2
V = sqrt400 = 20 m/s
The centripetal force is
(acceleration)*(Mass) = 2*2500 = 5000 N
Centrifugal acceleration is the opposite of centripetal acceleration