x = x initial + initial speed* t + (1/2) a t^2
here
0.80 = 0 + 0 + (1/2)(6.5) t^2
1.6/6.5 = t^2
t = sqrt (1.6 / 6.5)
not long
A .250 kg ice puck starting from rest slides down a .80 m frictionless incline with a uniform acceleration of 6.5 m/s2. How long does it take the ice puck to reach the bottom of the ramp?
1 answer