Asked by chemistry
A 250.0 - ml aqueous solution contains 45.1 µg of a pesticide . Express the pesticide's concentration in weight percent , parts per million , and parts per billion .
Answers
Answered by
DrBob222
It would be nice to have the density and to know the volume of water. Assuming 45.1 ug is so small and that the 250 mL of solution has a mass of 250 g, then % w/w = (mass solute/total mass)*100 = (45.1E-6g/250 g)*100.
Remember that percent w/w is parts per 100 (that's parts per 10^2). Multiply by 10,000(that's 10^4) to get ppm or by 10.000,000 (that's 10^7) to get ppb.
A quickie way I convert to ppm is 1 ppm = 1 mg/L which is a % w/v. That would be 45.1E-6 g or 0.0451 mg/250 mL = ? ppm
For dilute solutions ppm w/v and ppm w/w are essentially the same.
Remember that percent w/w is parts per 100 (that's parts per 10^2). Multiply by 10,000(that's 10^4) to get ppm or by 10.000,000 (that's 10^7) to get ppb.
A quickie way I convert to ppm is 1 ppm = 1 mg/L which is a % w/v. That would be 45.1E-6 g or 0.0451 mg/250 mL = ? ppm
For dilute solutions ppm w/v and ppm w/w are essentially the same.
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