A 250.0 kg roller coaster car has 20,000 J of potential energy at the top of the hill. Neglecting frictional losses, what is the velocity of the car at the bottom of thee hill?

Question

A.) 9.8 m/s
B). 12.6 m/s
C). 14.1 m/s
D). 8.9 m/s

Answer 1

Assuming the car has no kinetic energy at the top...
energy at the bottom = energy at the top
energy at the bottom = kinetic energy
kinetic energy = (1/2) * m * (v^2)
So,
(1/2)*m*(v^2)=20,000J
Solve for v