A 25 ml solution containing oxalate, C204²‐ was titrated with KMnO4 solution in acidic medium. C2O4²- ions were oxidized to CO2 and KMnO4 ions were reduced to Mn2+ ions. If 30.50 ml of 1.25M KMnO4 solution is required for the solution. Calculate the concentration of the solution containing C2O4²- ions.

Answer 1

2[MnO4]^- + 5[C2O4]^2- + 16H^+ ===> 2Mn^2+ + 10CO2 + 8H2O
moles KMnO4 = M x L = 1.25 M x 0.03050 L = 0.03813
mols C2O4^2- = 0.03813 moles MnO4^2- x (5 mols C2O4^2-/2 mols MnO4^-) = 0.03813 x 5/2 = 0.09531, then
(C2O4^2-) = mols/L = 0.09531/0.025 = ? M
Check my arithmetic.