M*g = 25 * 9.8 = 245 N. = Wt. of child.
At bottom of slide:
a. PE = Mg*h = 245*4 = 980 J.
b. KE = 0.5M*V^2 = 0.5*25*5^2 = 312.5 J.
c. PE-KE = Energy lost to friction.
A 25-kg child sits at the top of a
4-meter slide. After sliding down, the child is traveling at 5 m/s. How much PE does he start with? How much KE does he end with? How much energy is lost to friction?
if you push a box across the floor with a force of 30 N you push it 15 meters in 8 seconds how much work will you do how much power did you use?
1 answer
1 answer