KE = 0.5M*V^2 = 0.5*0.025*80^2 = 80 J.
F*d = F*1 = 80 J.
F = 80 N.
A 25 gram arrow fired from a bow has a speed of 80m/s. The energy in the arrow came from work done by the bow that acted over a 1m "draw" distance. What average force acted on the arrow over this distance
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