h^2 + x^2 = 625 at t = 0 x=20so h = 15
2 h dh + 2 x dx = 0
dh = -(x/h) dx
dh/dt = -(20/15 ) dx/dt = -(20/15).18
A 25-ft ladder rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 0.18 ft/sec, how fast, in ft/sec, is the top of the ladder sliding down the wall, at the instant when the bottom of the ladder is 20 ft from the wall? Answer with 2 decimal places.PLZ HELP
2 answers
what is the answer? .24?
2 answers