A 25.00 mL volumetric pipet is rinsed with deionized water. Several drops of water remain in the pipet. It is then used to deliver a 25.00 mL aliquot of the KHP solution into the Erlenmeyer flask in which the sample will be titrated. How will this affect the results of the calculated concentration?

Answer 1

I assume you are determining the molarity of NaOH.The pipet was contaminated with water. When it delivered 25.00 mL of the KHP for titration with NaOH, it has fewer mols KHP than you entered for the calculation.
Your calculation was
mL NaOH x M NaOH = grams KHP/molar mass KHP = mols KHP.
M NaOH = mols KHP/mL NaOH
So you put in too large a number for mols KHP, you actually fewer so it takes less volume NaOH. so the numerator is too large, the denominator is too small so the M NaOH ends up too large.