A 25.0 mL sample of 0.100 M propanoic acid (HC3H5O2, Ka = 1.3 ✕ 10-5) is titrated with 0.100 M KOH solution.

Question

A) 8.0ml
B) 12.5 ml
C) 20.0 ml
D) 25.0 ml
E) 25.1 ml
F) 28.0 ml

Answer 1

and the question is? If it is the volume of KOH, then
NoralityAcid*VolumeAcid=NormalityBase*VolumeBAse
.1*25ml=.1*Vb
vb=25ml