sketch a diagram. How how off the ground is the child at the 30 deg point:
Ans: h=2(1-cos30)
a. child speed at bottom: KE=initialPE
1/2 m v^2=mgh
v= sqrt (2gh)
b. energy lost: initial PE-1/2 m(2)^2
A 25.0-kg child on a 2.00-m-long swing is released from rest when the ropes of the swing make an angle of 30.0° with the vertical. (a) Neglecting friction, find the child’s speed at the lowest position. (b) If the actual speed of the child at the lowest position is 2.00 m/s, what is the mechanical energy lost due to friction?
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NOOB
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