A 25.0 g aluminum block is warmed to 65.2 C and plunged into an insulated beaker containing 55.3g of water initially at 22.0C. the aluminum and water are allowed to come to thermal equilibrium. Assuming that no heat is lost, what is the final temperature of the water and aluminum?

3 answers

the sum of heats gained is zero (one will give off heat, or negative heat gained)

massal*specificheatAl*(Tf-65.2)+masswater*c*(Tf-22)=0

solve for Tf

6742.8

25.8 degrees Celsius

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