at the bottom, v^2 = 2gh
PE at top is mgh = 24*5*9.8
KE at bottom is 1/2 mv^2 = 1/2 * 24 * 2.8^2
loss to friction is PE-KE
A 24 kg child descends a 5 m high slide and reaches the ground with a speed of 2.8 m/s. How much energy was dissipated due to friction in the process?
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