a=F/m so F and m would have to go up at the same rate to keep the same ration.
F/m=F/m
F/3180=8340/2340
solve for F
A 2340 kg car traveling to the west at 20.7
m/s slows down uniformly under a force of
8340 N to the east.
a) How much force would be required to
cause the same acceleration on a car of mass
3180 kg?
Answer in units of N.
b) How far would the car move before stop-
ping?
Answer in units of m.
1 answer
1 answer