A 23- bullet traveling 230 penetrates a 3.6 block of wood and emerges cleanly at 170 . If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?

Question

A 23- bullet traveling 230  penetrates a 3.6  block of wood and emerges cleanly at 170 . If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?

Damon · Answer

initial momentum = final momentum 23 * 230 = 23 * 170 + 3.6 * v solve for v

Anonymous · Answer

1.351696648 m/s