A 221-kg log is pulled up a ramp by means of a rope that is parallel to the surface of the ramp. The ramp is inclined at 27.7° with respect to the horizontal. The coefficient of kinetic friction between the log and the ramp is 0.811, and the log has an acceleration of 0.876 m/s2. Find the tension in the rope.

1 answer

forces upward: Tension+friction-gravity down
but friction=mg*cosTheta*mu
and gravity down=mg*sinTheta

net force=mass*acceleration
Tension+mg*cosTheta*mu
- mg*sinTheta = mass*acceleration

solve for tension