To determine the tension force in the second rope, we can use Newton's second law of motion, \(F = ma\).
Step 1: Calculate the total mass being pulled.
The total mass consists of the airplane and both gliders:
\[ m_{\text{total}} = m_{\text{airplane}} + m_{\text{glider 1}} + m_{\text{glider 2}} = 2200, \text{kg} + 350, \text{kg} + 250, \text{kg} = 2800, \text{kg} \]
Step 2: Calculate the total force acting on the system.
Using Newton's second law, we can find the total force required to accelerate this mass:
\[ F_{\text{total}} = m_{\text{total}} \cdot a = 2800, \text{kg} \cdot 1.3, \text{m/s}^2 = 3640, \text{N} \]
Step 3: Consider the forces on the second glider.
Now, we examine the forces acting on the second glider (the glider with mass \(250, \text{kg}\)). The total force acting on it can be expressed as:
\[ F_{\text{tension}} - F_{\text{glider}} = m_{\text{glider}} \cdot a \]
Where:
- \(F_{\text{tension}}\) is the tension in the second rope (which we need to find),
- \(F_{\text{glider}} = m_{\text{glider}} \cdot g\) only applies if we are considering weight in a vertical direction, and since we neglect friction and are in horizontal linear motion, we skip that consideration here.
Step 4: Apply Newton's second law to the second glider.
Substituting our values for the second glider \(F_{\text{tension}} - 0 = m_{\text{glider}} \cdot a\):
\[ F_{\text{tension}} = m_{\text{glider}} \cdot a \]
Where:
- \( m_{\text{glider}} = 250, \text{kg} \)
- \( a = 1.3, \text{m/s}^2 \)
Step 5: Calculate the tension force.
\[ F_{\text{tension}} = 250, \text{kg} \cdot 1.3, \text{m/s}^2 = 325, \text{N} \]
Conclusion
The magnitude of the tension force in the second rope is:
\[ \boxed{325, \text{N}} \]