delta L/L = (T/area) / E
= (215*9.81 /2*10^-5) / 8*10^10
= ( 1054 * 10^5 ) / 8*10^10
= 132 * 10-5
so
delta L = (3.5)(132*10^-5)
= 461 * 10^-5
= .00461 meters = .461 cm
A 215-kg load is hung on a wire of length of 3.50 m, cross-sectional area 2.000x10^-5 m2, and Young's modulus 8.00x 10^10 N/m2. What is its increase in length?
1 answer