A 2100 kg car traveling at 12.0 m/s collides with a 2780 kg car that is initially at rest at the stoplight. The cars stick together and move 3.90 m before friction causes them to stop. Determine the coefficient of kinetic friction betwen the cars and the road, assuming that the negative acceleration is constant and that all wheels on both cars lock at the time of impact.

1 answer

M1*V1 + M2*V2 = M1*V + M2*V
2100*12 + 2780*0 = 2100V + 2780V
25,200 = 4880V
V = 5.16 m/s.

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