conservation of momentum says that the result is
2050(2.3i+0j)+1200(0i+4.5j)+1600(10i+j) = (2050+1200+1600)(ai+bj)
4715i+5400j+16000i = 4850(ai+bj)
20715i+5400j = 4850(ai+bj)
4.27i+1.11j = ai+bj
speed is 4.42 m/s
direction E14.5°N
A 2050 kg truck is traveling east through an intersection at 2.3 m/s when it is hit simultaneously from the side and the rear. (Some people have all the luck!) One car is a 1200 kg compact traveling north at 4.5 m/s. The other is a 1600 kg midsize traveling east at 10 m/s. The three vehicles become entangled and slide as one body. What are their speed and direction just after the collision?
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