A 200W laptop is connected to a 240v Ac line

Question

1.calculate the RMS current flowing from the outlet
2.Determine the peak current
3.calculate the peak voltage
4.calculate the maximum power delivered from the Ac line

Answer 1

To calculate these values, we can use the formula:

Power (P) = Current (I) * Voltage (V)

1. Calculating the RMS current flowing from the outlet:
Since the power of the laptop is given as 200W and the voltage is 240V, we can rearrange the formula to solve for current:

I = P / V

I = 200W / 240V

I ≈ 0.833 A (rounded to three decimal places)

Therefore, the RMS current flowing from the outlet is approximately 0.833 A.

2. Determining the peak current:
The peak current can be calculated by multiplying the RMS current by the square root of 2 (sqrt(2)):

Peak Current (Ip) = RMS Current (Irms) * sqrt(2)

Ip = 0.833 A * sqrt(2)

Ip ≈ 1.178 A (rounded to three decimal places)

Therefore, the peak current is approximately 1.178 A.

3. Calculating the peak voltage:
The peak voltage can also be calculated using the formula:

Peak Voltage (Vp) = RMS Voltage (Vrms) * sqrt(2)

However, the RMS voltage is not provided in this scenario. Assuming it is the same as the supplied voltage (240V), we can calculate the peak voltage as follows:

Vp = 240V * sqrt(2)

Vp ≈ 339.411 V (rounded to three decimal places)

Therefore, the peak voltage is approximately 339.411 V.

4. Calculating the maximum power delivered from the AC line:
The maximum power delivered from the AC line can be determined using the formula:

Maximum Power (Pmax) = RMS Current (Irms) * RMS Voltage (Vrms)

Pmax = 0.833 A * 240V

Pmax ≈ 199.92 W (rounded to two decimal places)

Therefore, the maximum power delivered from the AC line is approximately 199.92 W.