A 200-Ù resistor, 40.0-mH inductor and a 2.00-ìF capacitor are connected in series with a 120-V rms source at 1000 Hz. What is the phase angle of this circuit?

Answer 1

Z= R + jXl - jXc

so figure Xl and Xc, those are just formulas.

then the angle...well...I assume you mean the angle between current and voltage...

Figure Z=Zmagnitude@angle
where angle= arctan(Xl-Xc)/R

then I=(V@0)/Z@angle= =(V/Zmagnitude)@(-angle)

and I suppose you are just interested in the negative of angle.