A 200-kg crate is moved across a frictionless floor by applying a net force of 70 N for 5 seconds. This results in a final speed of 3 m/s after the crate moves a distance of 5m. What is the final kinetic energy of the crate?
3 answers
KE=(mv^2)/2 = (200*3^2)/2 = 900J
The above is corect
The above is correct.