A 200.0mL solution with 3.1 x 10^-3

mol of MA will begin to precipitate at 19.4 C. Calculate each of
the following at this temperature.
a) Ksp
b)change in G

1 answer

A. I assume M^+ and A^- but it could be M^2+ and A^2- etc.
(MA) = 0.0031 x (1000 mL/200 mL) = 0.0031*5 = ?
Ksp = (M^+)(A^-) = (0.0031*5)^2

B. dG = -RT*lnK