A 20 kg block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 80 N to the left. As a result, the block accelerates at 2.5 m/s2. The coefficient of kinetic friction μk between the block and the table is ___ .( Round the answer to the nearest hundredth.)

Question

This is big boi stuff!

Answer 1

20 kg * 2.5 m/s^2 = 50 N

so the frictional force is ... 80 N - 50 N = 30 N

Ff = m * g * μk

μk = 30 N / (20 kg * 9.8 m/s^2) = 30 N / 196 N

the coefficient of friction is just a number ... no units

Answer 2

What is the answer rounded to the nearest hundred?

Answer 3

calculator broken??

Answer 4

Typically people would get numeric values for these types of questions. If you were to do the math on the calculator correctly you should get Syntax Error. It seems odd but i put that on all my tests and my teachers call my parents to let them know how good i am doing

Answer 5

Frictional force after calculation = 30N
Coefficient of friction = 0.15

Answer 6

0.15