Area loop=PI*radius^2=PI*.1^2 m^2
Area=.01PI m^2
flux=B*area=.0057*PI
"Plane of Loop" I suspect you mean the plane the loop is contained in. Normally, in vectors, we deal with the diretion of the loop to be the NORMAL to that plane. Angle of Plane to flux lines then must be 48deg to flux lines
flux=BAcos48
A 20-cm-diameter circular loop of wire is placed in a 0.57-T magnetic field.
Part A
When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop?
Part B
The plane of the loop is rotated until it makes a 42 ∘ angle with the field lines. What is the angle in the equation ΦB = BAcosθ for this situation?
Part C
What is the magnetic flux through the loop at this angle?
1 answer
1 answer