a 2 kg object moving at 5 m/s enters a surface with the coefficient of kinetic friction is .1 and is brought to a full stop. If the cart moved 12.8 m calculate:

a) the net work done on the object over the 12.8 m distance (I got 6.4j, but it's probably wrong)

b) change in kinetic energy of the object

c) in what form of energe was the kinetic energy changed?

1 answer

Net work=mu*m*g*distance

change KE=KEinitial-KEfinal=KEinitial-0

friction results in heat.