1) p=mv=2•4= 8 kg•m/s
2) KE=mv²/2
3) At elastic collision
p= - mv
4) Δp= p1-(-p2) =mv – (-mv)= 2mv
5) p(wall)= Δp=2mv
6) F•Δt=mv
F= mv/ Δt
A 2 kg cart rolls across the floor and runs into the wall and sticks. Before the collision the cart has a velocity of 4 m/s in the x direction. The collision took place in 0.1 s.
1) What was the cart's momentum before the collision?
2) What was the cart's KE before the collision?
3) What was the momentum after the collision?
4)What was the change in the cart's momentum?
5) What was the impulse delivered to the car by the wall?
6) What was the average force exerted on the wall by the car?
PLEASE HELP ME!!!
its a direct answer.
1 answer