The force down the plane is mgSinTheta or mg (1/2). The speed will be ...
Vf^=2 a d = 2*1/2 mg/m
vf= sqrt g
check my reasoning.
A 2 kg block, starting from the rest, slides 20 m down frictionless inclined plane, dropping a distance of 10m.
The magnitude of the net force on the block while it is sliding is...?
How do I solve this problem?
And if it were to ask for the speed at the bottom of the incline, how would I find that?
Thanks!
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