A 2 kg ball is launched upward and has a kinetic energy of 25 J. Solve for the velocity of the ball as it

was launched.

5 m/s

12.5 J

25 J

50 m/s

1 answer

To calculate the velocity of the ball as it was launched, we can use the formula for kinetic energy:

\[ KE = \frac{1}{2}mv^2 \]

Where:

  • \( KE \) is the kinetic energy (25 J in this case),
  • \( m \) is the mass of the ball (2 kg),
  • \( v \) is the velocity we want to find.

We can rearrange the formula to solve for \( v \):

\[ v = \sqrt{\frac{2 \times KE}{m}} \]

Substituting the known values:

\[ v = \sqrt{\frac{2 \times 25 , \text{J}}{2 , \text{kg}}} \]

\[ v = \sqrt{\frac{50}{2}} \]

\[ v = \sqrt{25} \]

\[ v = 5 , \text{m/s} \]

Therefore, the velocity of the ball as it was launched is 5 m/s.