A 2μC charge is positioned at x = -0.8m and another 2μC charge is positioned at x = 0.8m. A positive test charge of q = 1.28*10^-18C is positioned at the origin x = 0m. Find (a) the electric force exerted on q, (b) the electric field at the origin, and (c) the electric potential at the origin.
My work and calculations:
(a) ∑F = -F1 + F2
= -(kq1q/r^2) + (kq2q/r^2)
= kq((-q1/r^2)+(q2/r^2))
I noticed that the terms in the brackets cancel out to 0. But that would result in ∑F = 0N. I'm not sure if I'm doing this correctly... Could someone please help me?
1 answer
it is zero. Think..you have two positive charges equidistant on opposite sides...
1 answer