A 2.9 L sample of gas has a pressure of 5 atm and a temperature of 50 °C. What will be the new temperature in Kelvin if the volume is decreased to 2.4 L and the pressure decreased to 3 atm? Round to the nearest whole number. Don't forget the units.
4 answers
(P1V1/T1) = (P2V2/T2)
P1V1/T1 = P2V2/T2
P1 = 5 atm, V1 = 2.9L, T1 = 273+50 = 323K
P2 = 3 atm, V2 = 2.4L, T2 = ?
5*2.9/323 = 3*2.4/T2
T2 = 3*2.4*323/5*2.9
= 160.4K
P1 = 5 atm, V1 = 2.9L, T1 = 273+50 = 323K
P2 = 3 atm, V2 = 2.4L, T2 = ?
5*2.9/323 = 3*2.4/T2
T2 = 3*2.4*323/5*2.9
= 160.4K
Wrong
It’s right just the steps are not clear
2 answers