A 2.70 g sample of solid Ni(CN)2⋅4H2O was heated such that the water turned to steam and was driven off. Assuming ideal behavior, what volume would that steam occupy at 1.00 atm and 100.0 °C?

1 answer

mm = molar mass
grams H2O liberated = 2.70 g Ni(CN)2.4H2O x (4*mm H2O/mm Ni(CN)2.4H2O) = ? g H2O
Then mols H2O = grams H2O liberated/mm H2O and substitute into the following for n and solve for V in liters. Remember to convert T to kelvin which is 273 + 100 C = 373 K
Then use PV = nRT