Steel ρ₁ =7800 kg/m³
V₁=m₁/ρ₁=2.6/7800 = 3.3•10⁻⁴ m³
Gasoline ρ₂ = 750 kg/m³
m₂=ρ₂V₂=750•15•10⁻³ =11.25 kg
ρ(ave) =( m₁+m₂)/(V₁+V₂) =
=(2.6+11.25)/ (3.3•10⁻⁴+15•10⁻³) =
=13.85/0.01503=921 kg/m³
The final answer depends on the reference values of densities:
the density of gasoline ρ = 700 – 770 kg/m³ and the density of steel
ρ = 7400 – 8000 kg/m³
A 2.60 kg steel gas can holds 15.0 L of gasoline when full. What is the average density(kg/m^2))of the full gas can, taking into account the volume occupied by steel as well as by gasoline?
1 answer