A 2.6 kg block slides down a 25° inclined plane with constant acceleration. The block starts from rest at the top. At the bottom, its velocity is 0.80 m/s. The incline is 1.6 m long.
(a) What is the acceleration of the block?
m/s2
wb=m*g=2.6*9.8=25.48
fp=25.48sin25=10.77n
Fn=25.48cos25=23.09n
a=v^2-Vo^2/2.6= 0.64??? says wrong..???
(b) What is the coefficient of friction?
Cant do this one w/o acceleration please help!!!!