KE=1/2mv^2
KE=1/2(2.5kg)(5.7m/s)
KE=40.6J=1.230x10^-4kg
A 2.6 kg block of ice at a temperature of 0.0�C
and an initial speed of 5.3 m/s slides across a
level floor.
If 3.3 × 105 J are required to melt 1.0 kg
of ice, how much ice melts, assuming that the
initial kinetic energy of the ice block is entirely
converted to the ice’s internal energy?
1 answer