F=ma, where a is the net acceleration
2.2 * 3.3 = 7.26
That means that drag used up the other 0.89 N
A 2.20kg toy plane takes off with an acceleration of 3.30m/s2 . The engine supplies a force of 8.15N . Determine the magnitude of drag force acting on the plane as it accelerates.
2 answers
Fe - Fg = M*a,
8.15 - Fg = 2.2 * 3.3,
Fg = 0.89 N. = Drag force.
8.15 - Fg = 2.2 * 3.3,
Fg = 0.89 N. = Drag force.