A 2,200-kg car moving east at 10.0 m/s collides with a 3,000-kg car moving north. The cars stick together and move as a unit after the collision, at an angle of 35.0° north of east and at a speed of 5.16 m/s. Find the speed of the 3,000-kg car before the collision.

Answer 1

before
East momentum = 22000
North momentum = 3000 v

after
East momentum = 5200 (5.16 cos 35)
North momentum =5200 (5.16 sin 35)

so
3000 v = 5200 (5.16 sin 35)
solve for v

Answer 2

67