A 2.2 m-long string is fixed at both ends and tightened until the wave speed is 50 m/s.What is the frequency of the standing wave shown in the figure?

Question

picture has 6 waves

Answer 1

If it is truly six waves, then the 2.2m is six wavelengths long.

f*Lambda=50

Answer 2

how did you arrive at 50 because picture might have 7 nodes

Answer 3

50 was given as wavespeed.
I cant determine how many wavelengths the string is, you will have to do that.

Answer 4

but how do i do it

Answer 5

Count the cycles. From equilibrium up to the crest, down the trough, and back to equilibrium (like a complete sinusoidal wave)--that is one cycle.

Find the time: the distance of the string, divide it by the speed. This is the basic concept of velocity=displacement/time. You just solve for time.

You have seconds and you have cycles. What is frequency? Cycles per second. There.