A 2.00-kg stone attached to a rope 4.00 m long is whirled in a circle horizontally on a

frictionless surface, completing 5.00 revolutions in 2.00 s. Calculate the magnitude of
tension in the rope.

1 answer

The centripetal force acting on the stone is provided by the tension in the rope. The centripetal force can be calculated using the formula:

F = (m*v^2) / r

Where:
F = centripetal force
m = mass of the stone = 2.00 kg
v = tangential speed = (2πr*5) / t = (2π*4*5) / 2 = 20π m/s
r = radius of the circle = 4.00 m

Now, we can calculate the centripetal force:

F = (2.00 * (20π)^2) / 4.00
F = 800π^2 N

Therefore, the magnitude of tension in the rope is equal to the centripetal force:

T = 800π^2 N
T ≈ 2500 N