I will assume that because here is no friction, the ball DOES NOT ROLL.
(1/2) k x^2 = .5 * 750 * .28^2 = 29.4 J check
Ke = (1/2) m v^2 = 29.4
.5 * 2 * v^2 = 29.4
v = 5.42 m/s
m g h = 29.4
2 * 9.81 * h = 29.4
h = 1.5 meters up
A 2.0 kg ball is placed against a spring of force constant 750N/m, which has been compressed 0.28m. The spring is released and the ball moves along a horizontal frictionless surface and up a ramp. Calculate the...
a) maximum elastic potential energy of the spring (could it be 29.4J, as that's what I've calculated?)
b) maximum velocity of the ball
c) maximum vertical height of the ball on the ramp
Please explain! I want to understand this! Thank you! :)
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